# 3. The formula h(t)= -16t^2+48t+160 gives the height of an object thrown from a building where t is measured in seconds

Excerpt
d. When does the object reach its maximum height?( wch coordinate of the vertex gives us that information) e. What is the maximum height reached by the object? (wch coordinate of the vertex gives us that information?) f. when is the object 175 feet gh?

3. The formula h(t)= -16t^2+48t+160 gives the height of an object thrown from a building where t is measured in seconds and h is measured in feet. a. First, let’s draw the parabola again h(t)= -16t^2+48t+160 and label the x-axis as time in seconds and the y-axis as height in feet. Label the intercepts and the vertex. b. How tall is the building the object is thrown from? ( in other words, we are interested in how gh is the object when t=0 right before it leaves the top of the building) c. After how many seconds does the object t the ground? d. When does the object reach its maximum height?( wch coordinate of the vertex gives us that information) e. What is the maximum height reached by the object? (wch coordinate of the vertex gives us that information?) f. when is the object 175 feet gh?