[N 2 ] = 1.00 M, [H 2 ] = 1.00 M, [NH 3 ] = 4.00 M 5a.) What is

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E 5c) It is too hard to solve ts problem for x! So I am going to give you the answer. The value of x turns out to be 0.279. Notice that x cannot ever be greater than 0.33 (or 1/3) – why is that?

[N 2 ] =  1.00 M,  [H 2 ] =  1.00 M,  [NH 3 ] = 4.00 M 5a.) What is Qc at ts point? Wch way will the reaction go? 5b.) if x is the concentration of N2 that reacts, fill in the rest of the ice chart at left. Now, suppose that the N 2 concentration is increased to 300 M.  The ICE setup would look like ts: N 2 (g)  +  3 H 2 (g)  2 NH 3 (g) I           300            1                      4 C E 5c) It is too hard to solve ts problem for x!  So I am going to give you the answer.  The value of x turns out to be 0.279.  Notice that x cannot ever be greater than 0.33 (or 1/3) – why is that? [N 2 ] =  1.00 M,  [H 2 ] =  1.00 M,  [NH 3 ] = 4.00 M 5a.) What is Qc at ts point? Wch way will the reaction go? 5b.) if x is the concentration of N2 that reacts, fill in the rest of the ice chart at left. Now, suppose that the N 2 concentration is increased to 300 M.  The ICE setup would look like ts: N 2 (g)  +  3 H 2 (g)  2 NH 3 (g) I           300            1                      4 C E 5c) It is too hard to solve ts problem for x!  So I am going to give you the answer.  The value of x turns out to be 0.279.  Notice that x cannot ever be greater than 0.33 (or 1/3) – why is that?

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