# Transcribed Image Text: In an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500

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Assume i(t) is in amps and t is in seconds. Do not include units in your answer.) i(t) = (0.129)sin(1000t – 0.64) (d) Repeat the calculations with C changed to 0.28 pF. z = 685.5 A 0 = 0.148 i(t) = (0.140) sin(1000nt – 0.58) |

Transcribed Image Text: In an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively, and R = 520 0, L = 0.22 H, and C = 2.8 pF.

(a) What is the impedance of the circuit (in 0)?

776.8

(b) What is the amplitude of the current from the source (in A)?

0.120

A

(c) If the emf of the source is given by v(t) = (100 V)sin(1,000nt), how does the current vary with time? (Use the following as necessary: t. Assume i(t) is in amps and t is in seconds. Do not include units in your answer.)

i(t) =

(0.129)sin(1000t – 0.64)

(d) Repeat the calculations with C changed to 0.28 pF.

z = 685.5

A

0 = 0.148

i(t) = (0.140) sin(1000nt – 0.58)

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